Thursday, October 19, 2017

Regular Expression in Java to check numbers in String - Example

Regular Expression to check numeric String
In order to build a regular expression to check if String is number or not or if String contains any non digit character or not you need to learn about character set in Java regular expression, Which we are going to see in this Java regular expression example. No doubt Regular Expression is great tool in developer arsenal and familiarity or some expertise with regular expression can help you a lot. Java supports regular expression using java.util.regex.Pattern and java.util.regex.Matchter class, you can see a dedicated package java.util.regex for regular expression in Java. Java supports regex from JDK 1.4, means well before Generics, Enum or Autoboxing. If you are writing server side code in Java programming language than you may be familiar with importance of regular expression which is key in parsing certain kind of messages e.g. FIX Messages used in Electronic trading. In order to parse Repeating groups in FIX protocol you really needs understanding of regular expression in Java. Any way In order to learn validating numbers using regular expression we will start with simple example

1) Check if a String is a number or not using regular expression
to clarify requirement, an String would be number if it contains digits. we have omitted decimal point and sign or + or - for simplicity.

If you are familiar with predefined character class in Java regular expression that you must know that \d will represent a digit (0-9) and \D will represent a non digit (anything other than 0 to 9). Now using this predefined character class, an String will not be a number if it contains any non digit characters, which can be written in Java regular expression as:

Pattern pattern = Pattern.compile(".*\\D.*");

which checks for non digit character anywhere in the String. This pattern return true if String contains any thing other than 0-9 digit, which can be used to know if an String is number or not using regular expression.

Same regular expression for checking String for numbers can also be written without using predefined character set and using character class and negation as shown in following example :

Pattern pattern = Pattern.compile(".*[^0-9].*");

This is similar to above regex pattern, only difference is \D is replaced by [^0-9]. By the way there is always multiple ways to check for certain things using regex.

2. Verify if an String is a six digit number or not using regular expression
This is kind of special regular expression requirement for validating data like id, zipcode or any other pure numerical  data. In order to check for digit you can either use character class [0-9] or use short form \d. here is simple regular expression in Java which can check if an String contains 6 digits or not:

Pattern digitPattern = Pattern.compile("\\d\\d\\d\\d\\d\\d");

above pattern checks each character for digit six times. This pattern can also be written in much shorter and readable format as :

Pattern digitPattern = Pattern.compile("\\d{6}");

where {6} denote six times. you can also replace \d with character class [0-9] and it should work.

Code Example - Regular expression in Java to check numbers

Java Regular Expression Example to check if String contains numbersHere is complete code example in Java programming language to check if a String is an integer number or not. In this Java program we are using regular expression to check if String contains only digits i.e. 0 to 9 or not. If String only contains digit than its number otherwise its not a numeric String. One interesting point to note is that this regular expression only checks for integer number as it not looking for dot(.) characters, which means floating point or decimal numbers will fail this test.

import java.util.regex.Pattern;
 * Java program to demonstrate use of Regular Expression to check
 * if a String is a 6 digit number or not.

public class RegularExpressionExample {
    public static void main(String args[]) {
        // Regular expression in Java to check if String is number or not
        Pattern pattern = Pattern.compile(".*[^0-9].*");
       //Pattern pattern = Pattern.compile(".*\\D.*");
       String [] inputs = {"123", "-123" , "123.12", "abcd123"};
       for(String input: inputs){
           System.out.println( "does " + input + " is number : "
                                + !pattern.matcher(input).matches());
       // Regular expression in java to check if String is 6 digit number or not
       String [] numbers = {"123", "1234" , "123.12", "abcd123", "123456"};
       Pattern digitPattern = Pattern.compile("\\d{6}");       
       //Pattern digitPattern = Pattern.compile("\\d\\d\\d\\d\\d\\d");

       for(String number: numbers){
           System.out.println( "does " + number + " is 6 digit number : "
                               + digitPattern.matcher(number).matches());

does 123 is number : true
does -123 is number : false
does 123.12 is number : false
does abcd123 is number : false

does 123 is 6 digit number : false
does 1234 is 6 digit number : false
does 123.12 is 6 digit number : false
does abcd123 is 6 digit number : false
does 123456 is 6 digit number : true

That's all on using Java regular expression to check numbers in String. As you have seen in this Java Regular Expression example that its pretty easy and fun to do validation using regular expression.

Further Reading
Complete Java Masterclass
Regular Expression Fundamentals
Java In-Depth: Become a Complete Java Engineer!

Other Java tutorials you may find useful


Anonymous said...

Nice information indeed. But, if your application is small and you don't use pattern matching very frequently, String class's matches() method is a shortcut for above.

//Java docs
public boolean matches(String regex) {
return Pattern.matches(regex, this);

Please correct me if i am wrong.

Anonymous said...

Hello Javin, Can you please share How to ignore certain digits from any number e.g. I want to ignore only non zero digits, please suggest?

Can Yalkın said...

How about this solution:
public static boolean isDigit(char c){
int x=(int)c-(int)'0';
return false;
return true;


public static boolean isOnlyDigit(String s){

for(int i=0;i<s.length();i++){
return false;
return true;

public static void main(String[] args) {
String s="098234";


Prabin Timsina said...

public boolean containsOnlyDigits(String s) {

if (s.isEmpty()) return false;

for (int i = 0; i < s.length(); i++) {
char temp = s.charAt(i) - '0';
if (temp < 0 || temp > 9)
return false;

return true;

Vandana Mishra said...

Scanner scn = new Scanner(;
boolean flag = false;
System.out.println("Enter digits");
try {
Integer i = scn.nextInt();
} catch(InputMismatchException ie) {
flag = true;
if(!flag) {
System.out.println("All are digits");
} else {
System.out.println("All entries are not digit");

Anonymous said...

I have query
I want to give input like this {25,45} using array is it possible. for the main function i need to use numbers only.

Javin Paul said...

@Anonymous, it's not possible to give a Java program input like that i.e. {25, 45}, though you can write little bit code to achieve that. Since that is String, just write a parser which reads this string, split it and create an array of String. Alternatively, you can also check this post to learn how to pass array as input to Scanner.

Unknown said...

Your regex is incorrect. It should be ".*^[0-9]*." rather than ".*^[0-9].*"

Alekhya Bodla said...

private static void checkStringContainsOnlyDigits(String string) {
Double doub = Double.parseDouble(string);
} catch(NumberFormatException e){
System.out.println(" given string is alpha numeric");


EthZena said...

public static bool IsDigit(string strIsDigit)

foreach(char c in strIsDigit)
if (c < 48 || c > 57)
return false;
return true;

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